Math Olympiad Question | You should know how to solve this! #manojagarwal #mathsolympiad #empoweringwisdomchannel
To find the sum of consecutive natural numbers from 1 to n, you can use the formula for the sum of an arithmetic series:
Sum = (n/2) * [2a + (n-1)d]
In this case, a is the first term (1), n is the number of terms (36), and d is the common difference (1).
So, we have: Sum = (36/2) * [2(1) + (36-1)(1)] Sum = 18 * [2 + 35] Sum = 18 * 37 Sum = 666
Now, we have found that the sum of the numbers from 1 to 36 is 666. So, the square root of this sum is:
√(666) ≈ 25.80 (rounded to two decimal places)
So, the answer to the given expression is approximately 25.80.
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