Selina Concise Mathematics Class 6 ICSE Solved Exercise 22 (A) Fully Solved - 2 (i) to (ix)
2. Solve:
(i) x – 3 = 2
(ii) m – 2 = – 5
(iii) b – 5 = 7
(iv) a – 2.5 = – 4
(v) y – 3 (1 / 2) = 6
Solution:
(i) x – 3 = 2
x = 2 + 3
We get,
x = 5
Therefore, the value of x for x – 3 = 2 is 5
(ii) m – 2 = – 5
m = – 5 + 2
We get,
m = – 3
Therefore, the value of m for m – 2 = – 5 is – 3
(iii) b – 5 = 7
b = 7 + 5
We get,
b = 12
Therefore, the value of b for b – 5 = 7 is 12
(iv) a – 2. 5 = – 4
a = – 4 + 2. 5
We get,
a = – 1. 5
Therefore, the value of a for (a – 2. 5) = – 4 is – 1. 5
(v) y – 3 (1 / 2) = 6
This can be written as,
y – (7 / 2) = 6
y = 6 + (7 / 2)
y = (12 + 7) / 2
y = 19 / 2
y =
Therefore, the value of y for y – 3 (1 / 2) = 6 is
