ICSE Class 6 Selina concise Maths solution, Playing with Numbers, Exerci...

Exercise 9 A complete solution.  ICSE Class 6 Selina concise Maths solution, Playing with Numbers, Selina concise maths solution,

ICSE Class 6 Selina concise Maths solution, Playing with Numbers, Exercise 9 A complete solution.

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Selina concise maths solution,

Exercises of Selina Solutions Concise Mathematics Class 6 Chapter 9: Playing With Numbers

 

Exercise 9(A) Solutions

 

Exercise 9(B) Solutions

 

Exercise 9(C) Solutions

Access Selina Solutions Concise Mathematics Class 6 Chapter 9: Playing With Numbers

Exercise 9(A)

(Using BODMOS)

1. 19 – (1 + 5) – 3

Solution:

Given

19 – (1 + 5) – 3

On further calculation, we get

= 19 – 6 – 3

= 19 – 9

= 10

2. 30 × 6 ÷ (5 – 2)

Solution:

Given

30 × 6 ÷ (5 – 2)

On further calculation, we get

= 30 × 6 ÷ 3

= 30 × 2

= 60

3. 28 – (3 × 8) ÷ 6

Solution:

Given

28 – (3 × 8) ÷ 6

Calculating further, we get

= 28 – 24 ÷ 6

= 28 – 4

= 24

4. 9 – [(4 – 3) + 2 × 5]

Solution:

Given

9 – [(4 – 3) + 2 × 5]

We get

= 9 – [1 + 10]

= 9 – 11

= – 2

5. [18 – (15 ÷ 5) + 6]

Solution:

Given

[18 – (15 ÷ 5) + 6]

On further calculation, we get

= [18 – 3 + 6]

= 18 + 3

= 21

6. [(4 × 2) – (4 ÷ 2)] + 8

Solution:

Given

[(4 × 2) – (4 ÷ 2)] + 8

On further calculation, we get

= [8 – 2] + 8

= 6 + 8

= 14

7. 48 + 96 ÷ 24 – 6 × 18

Solution:

Given

48 + 96 ÷ 24 – 6 × 18

We get

= 48 + 4 – 6 × 18

= 48 + 4 – 108

= 52 – 108

= – 56

8. 22 – [3 – {8 – (4 + 6)}]

Solution:

Given

22 – [3 – {8 – (4 + 6)}]

On calculating further, we get

= 22 – [3 – {8 – 10}]

= 22 – [3 + 2]

= 22 – 5

= 17

9. 34 – [29 – {30 + 66 ÷ (24 –

$\begin{array}{l}\overline{28–26}\end{array}$

)}]

Solution:

Given

34 – [29 – {30 + 66 ÷ (24 –

$\begin{array}{l}\overline{28–26}\end{array}$

)}]

On further calculation, we get

= 34 – [29 – {30 + 66 ÷ (24 – 2)}]

= 34 – [29 – {30 + 66 ÷ 22}]

= 34 – [29 – {30 + 3}]

= 34 – [29 – 33]

= 34 – [-4]

= 34 + 4

= 38

10. 60 – {16 ÷ (4 × 6 – 8)}

Solution:

Given

60 – {16 ÷ (4 × 6 – 8)}

On further calculation, we get

= 60 – {16 ÷ (24 – 8)}

= 60 – {16 ÷ 16}

= 60 – 1

= 59

11. 25 – [12 – {5 + 18 ÷ (4 –

$\begin{array}{l}\overline{5–3}\end{array}$

)}]

Solution:

Given

25 – [12 – {5 + 18 ÷ (4 –

$\begin{array}{l}\overline{5–3}\end{array}$

)}]

By calculating further, we get

= 25 – [12 – {5 + 18 ÷ (4 – 2)}]

= 25 – [12 – {5 + 18 ÷ 2}]

= 25 – [12 – {5 + 9}]

= 25 – [12 – 14]

= 25 – [-2]

= 25 + 2

= 27

12. 15 – [16 – {12 + 21 ÷ (9 – 2)}]

Solution:

Given

15 – [16 – {12 + 21 ÷ (9 – 2)}]

On further calculation, we get

= 15 – [16 – {12 + 21 ÷ 7}]

= 15 – [16 – {12 + 3}]

= 15 – [16 – 15]

= 15 – 1

= 14